Check Armstrong Number in Java

1import java.util.Scanner;
2
3public class Main {
4    public static void main(String[] args) {
5        Scanner sc = new Scanner(System.in);
6
7        System.out.print("Enter a number: ");
8        int n = sc.nextInt();
9
10        int temp = n;
11        int digits = 0;
12        while (temp != 0) {
13            digits++;
14            temp /= 10;
15        }
16
17        temp = n;
18        int sum = 0;
19        while (temp != 0) {
20            int d = temp % 10;
21            int pow = 1;
22            for (int i = 0; i < digits; i++) {
23                pow *= d;
24            }
25            sum += pow;
26            temp /= 10;
27        }
28
29        if (sum == n) {
30            System.out.println(n + " is an Armstrong Number");
31        } else {
32            System.out.println(n + " is not an Armstrong Number");
33        }
34
35        sc.close();
36    }
37}