Armstrong Numbers in Range in Java

1public class Main {
2    private static boolean isArmstrong(int n) {
3        int temp = n;
4        int digits = 0;
5        while (temp != 0) {
6            digits++;
7            temp /= 10;
8        }
9        temp = n;
10        int sum = 0;
11        while (temp != 0) {
12            int d = temp % 10;
13            int pow = 1;
14            for (int i = 0; i < digits; i++) {
15                pow *= d;
16            }
17            sum += pow;
18            temp /= 10;
19        }
20        return sum == n;
21    }
22
23    public static void main(String[] args) {
24        for (int i = 1; i <= 1000; i++) {
25            if (isArmstrong(i)) {
26                System.out.print(i + " ");
27            }
28        }
29    }
30}