Array Max & Min in JavaScript

1// Method 1: Using Math.max and Math.min with spread operator
2let numbers = [10, 5, 20, 15, 8, 25];
3
4let max = Math.max(...numbers);
5let min = Math.min(...numbers);
6
7console.log("Array:", numbers);
8console.log("Maximum:", max);
9console.log("Minimum:", min);
10
11// Method 2: Using for loop
12function findMaxMin(arr) {
13    if (arr.length === 0) return { max: null, min: null };
14    
15    let max = arr[0];
16    let min = arr[0];
17    
18    for (let i = 1; i < arr.length; i++) {
19        if (arr[i] > max) max = arr[i];
20        if (arr[i] < min) min = arr[i];
21    }
22    
23    return { max, min };
24}
25
26let result = findMaxMin([10, 5, 20, 15, 8]);
27console.log("\nUsing loop:", result);
28
29// Method 3: Using reduce
30function findMaxMinReduce(arr) {
31    return arr.reduce((acc, num) => {
32        acc.max = Math.max(acc.max, num);
33        acc.min = Math.min(acc.min, num);
34        return acc;
35    }, { max: arr[0], min: arr[0] });
36}
37
38console.log("\nUsing reduce:", findMaxMinReduce([3, 7, 2, 9, 1]));
39
40// Method 4: Using sort
41function findMaxMinSort(arr) {
42    let sorted = [...arr].sort((a, b) => a - b);
43    return {
44        min: sorted[0],
45        max: sorted[sorted.length - 1]
46    };
47}
48
49console.log("\nUsing sort:", findMaxMinSort([12, 4, 8, 19, 3]));