Search in Array
Program to search for an element in an array
JavaScript Search in Array Program
This program helps you to learn the fundamental structure and syntax of JavaScript programming.
// Method 1: Using indexOf
let arr = [10, 20, 30, 40, 50];
let searchValue = 30;
let index = arr.indexOf(searchValue);
if (index !== -1) {
console.log(`${searchValue} found at index ${index}`);
} else {
console.log(`${searchValue} not found`);
}
// Method 2: Using includes
let numbers = [5, 10, 15, 20, 25];
console.log("\nUsing includes:");
console.log("15 exists:", numbers.includes(15));
console.log("35 exists:", numbers.includes(35));
// Method 3: Using find
let users = [
{ id: 1, name: "John" },
{ id: 2, name: "Jane" },
{ id: 3, name: "Bob" }
];
let user = users.find(u => u.id === 2);
console.log("\nUsing find:", user);
// Method 4: Using findIndex
let index2 = users.findIndex(u => u.name === "Bob");
console.log("\nFindIndex:", index2);
// Method 5: Using for loop
function searchArray(arr, value) {
for (let i = 0; i < arr.length; i++) {
if (arr[i] === value) {
return i;
}
}
return -1;
}
console.log("\nUsing loop:", searchArray([1, 2, 3, 4, 5], 3));
// Method 6: Binary search (sorted array)
function binarySearch(arr, target) {
let left = 0;
let right = arr.length - 1;
while (left <= right) {
let mid = Math.floor((left + right) / 2);
if (arr[mid] === target) {
return mid;
} else if (arr[mid] < target) {
left = mid + 1;
} else {
right = mid - 1;
}
}
return -1;
}
let sorted = [1, 3, 5, 7, 9, 11, 13];
console.log("\nBinary search:", binarySearch(sorted, 7));
// Method 7: Using some (check existence)
let hasEven = [1, 3, 5, 7, 8].some(num => num % 2 === 0);
console.log("\nHas even number:", hasEven);30 found at index 2
Using includes:
15 exists: true
35 exists: false
Using find: { id: 2, name: 'Jane' }
FindIndex: 2
Using loop: 2
Binary search: 3
Has even number: trueUnderstanding Search in Array
This program demonstrates different methods to search for elements in arrays.
Method 1: indexOf()
Finds first occurrence:
let index = arr.indexOf(value);
Returns:
Method 2: includes()
Checks existence:
arr.includes(value);
Returns:
Boolean (true/false)
Method 3: find()
Finds first matching element:
arr.find(item => condition);
Use case:
Objects, complex conditions
Method 4: findIndex()
Finds index of first match:
arr.findIndex(item => condition);
Returns:
Index or -1
Method 5: For Loop
Manual search:
for (let i = 0; i < arr.length; i++) {
if (arr[i] === value) return i;
}
return -1;Method 6: Binary Search
For sorted arrays only:
// Divide and conquer
// O(log n) time complexityHow it works:
Time Complexity:
Method 7: some()
Check if any element matches:
arr.some(item => condition);
Returns:
Boolean
When to Use:
-
indexOf/includes
: Simple value search
-
find/findIndex
: Objects, conditions
-
Binary search
: Sorted arrays, large data
-
some
: Existence check
-
Loop
: Custom logic, learning
Let us now understand every line and the components of the above program.
Note: To write and run JavaScript programs, you need to set up the local environment on your computer. Refer to the complete article Setting up JavaScript Development Environment. If you do not want to set up the local environment on your computer, you can also use online IDE to write and run your JavaScript programs.
Practical Learning Notes for Search in Array
This JavaScript program is part of the "Array Programs" topic and is designed to help you build real problem-solving confidence, not just memorize syntax. Start by understanding the goal of the program in plain language, then trace the logic line by line with a custom input of your own. Once you can predict the output before running the code, your understanding becomes much stronger.
A reliable practice pattern is to run the original version first, then modify only one condition or variable at a time. Observe how that single change affects control flow and output. This deliberate style helps you understand loops, conditions, and data movement much faster than copying full solutions repeatedly.
For interview preparation, explain this solution in three layers: the high-level approach, the step-by-step execution, and the time-space tradeoff. If you can teach these three layers clearly, you are ready to solve close variations of this problem under time pressure.