Largest Among Three Numbers in JavaScript

1// Method 1: Using if-else
2let a = 10, b = 25, c = 15;
3let largest;
4
5if (a >= b && a >= c) {
6    largest = a;
7} else if (b >= a && b >= c) {
8    largest = b;
9} else {
10    largest = c;
11}
12
13console.log("Largest among", a + ",", b + ",", c, "is:", largest);
14
15// Method 2: Using Math.max()
16let num1 = 10, num2 = 25, num3 = 15;
17let max = Math.max(num1, num2, num3);
18console.log("Largest using Math.max():", max);
19
20// Method 3: Using function
21function findLargest(x, y, z) {
22    if (x >= y && x >= z) {
23        return x;
24    } else if (y >= x && y >= z) {
25        return y;
26    } else {
27        return z;
28    }
29}
30
31console.log("Largest:", findLargest(5, 8, 3));
32
33// Method 4: Using array and spread operator
34function findLargestArray(...numbers) {
35    return Math.max(...numbers);
36}
37
38console.log("Largest from array:", findLargestArray(10, 25, 15, 30, 5));