Check Palindrome Number
Check whether a number is a palindrome (same forwards and backwards).
Java Check Palindrome Number Program
This program helps you to learn the fundamental structure and syntax of Java programming.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number: ");
int n = sc.nextInt();
int temp = n;
int rev = 0;
while (temp != 0) {
int d = temp % 10;
rev = rev * 10 + d;
temp /= 10;
}
if (rev == n) {
System.out.println(n + " is a Palindrome Number");
} else {
System.out.println(n + " is not a Palindrome Number");
}
sc.close();
}
}Enter a number: 121 121 is a Palindrome Number
Understanding Check Palindrome Number
We reverse the digits and compare with the original number.
Note: To write and run Java programs, you need to set up the local environment on your computer. Refer to the complete article Setting up Java Development Environment. If you do not want to set up the local environment on your computer, you can also use online IDE to write and run your Java programs.
Practical Learning Notes for Check Palindrome Number
This Java program is part of the "Module 2: Conditional Programs" topic and is designed to help you build real problem-solving confidence, not just memorize syntax. Start by understanding the goal of the program in plain language, then trace the logic line by line with a custom input of your own. Once you can predict the output before running the code, your understanding becomes much stronger.
A reliable practice pattern is to run the original version first, then modify only one condition or variable at a time. Observe how that single change affects control flow and output. This deliberate style helps you understand loops, conditions, and data movement much faster than copying full solutions repeatedly.
For interview preparation, explain this solution in three layers: the high-level approach, the step-by-step execution, and the time-space tradeoff. If you can teach these three layers clearly, you are ready to solve close variations of this problem under time pressure.