Count Digits Recursively
Count digits in a number using recursion.
IntermediatePhase 3 - Level 2: Advanced RecursionExample 1 of 10
count-digits-recursively.py
1def count_digits(n):2 # Base case3 if n == 0:4 return 056 # Recursive case7 return 1 + count_digits(n // 10)89# Test10num = int(input("Enter a number: "))11result = count_digits(abs(num))12print(f"Number of digits: {result}")
Output
Enter a number: 12345 Number of digits: 5
What's going on
Count = 1 + count of remaining digits.
Key Concepts:
Base case: 0 has 0 digits
Add 1 for current digit
Recurse on n // 10 (remove last digit)
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