Sum of First N Even Numbers Recursively

Calculate sum of first n even numbers recursively.

IntermediatePhase 3 - Level 2: Advanced RecursionExample 8 of 10
sum-of-first-n-even-numbers-recursively.py
1def sum_even(n):
2 # Base case
3 if n == 0:
4 return 0
5
6 # Recursive case
7 # nth even number is 2*n
8 return (2 * n) + sum_even(n - 1)
9
10# Test
11n = int(input("Enter n: "))
12result = sum_even(n)
13print(f"Sum of first {n} even numbers: {result}")

Output

Enter n: 5
Sum of first 5 even numbers: 30

What's going on

Nth even number is 2*n.

Key Concepts:

Base case: sum(0) = 0
Nth even number = 2*n
Add current even number to sum of previous